How Much Weight Can A 4x4 Hold

How much can a 2.40 meter long 4x4 weigh? 3

Make a deck with a bathtub

We say you're talking about four by four pieces of wood. (Four by four instead of 4 by 4 inches.) What kind of wood is this? Douglas went again. Do they treat you under pressure?

In both cases, the wood carries about 625 pounds per square inch. For a 12.25 square inch cross section, there are 3.5 on each side in a 4x4. 625 * 12.25 = 7656.25 pounds.

Most tea pots are about 500 gallons long. At 8 lbs / gal, that's 4000 lbs.

Of course, this means that the bathtub is just above 4x4. If you are building a patio with corner columns supporting other pieces of wood, you may need to do more complex calculations.

Also, always consider the safety factor of 2 or 3 (you do not want the item to almost break and you must also consider any defects in the wood that can significantly reduce its strength).

So let's deal with the 4x4 so that it can carry 7,500 pounds and use the 3's protective element. What's the weight of the rest of your deck? Probably less than the extra ,000 6,000.

I will definitely take a look at your final design. The mistake that can easily get your claim denied is to fail.

You ask how high the parallel compressive strength of a fiber is. Fur is famous because you did not mention the type of wood. If you use different types of wood, just determine the compression strength of each one and follow my calculations.

Uc (fir) = Uc = 7430 psi, fir compressive strength

A = 4 x 4 = 16 inches, 4X4 area

Ft = Uc x H = 7,430 psi x 16 in² = 118,880 lb, theoretical load

FS = 0.30, which means we want our theoretical maximum load to be 30% greater than our maximum safe load.

130/100 = Ft / F = 11,888,000 lb / f

130F =, 11,888,000

F = 91,446 pounds

The maximum equation is:

F = (Uc x A) / 1.30, where Uc is the compressive strength of the material used, A is the region and F is the capacity of our primary load.

Now you need to remember that this situation describes the load that is applied evenly and completely on the top of the 4x4. If the load is shifted to 4x4 with screws, nails or other fasteners, the optimal minimum load as well as the maximum protective load is reduced. Furthermore, if the wood has defects such as large twists or knots, etc., the theoretical and protective burden will be reduced. I cite my source for CPU Fir.

4 x 4 treated items