Bh4 Lewis Structure

What is the structure of the [BH4] ion in relation to VSEPR, as well as the dot and cross structure? ۔

I have a hard time making dot and cross diagrams for this ion, it doesn't seem like there are any electrons left to bind boron for the last hydrogen. please explain.

update

I know we need extra electrons because it is a negative ion, but where do these extra electrons come from?

It's not as bad as you think, nor as complicated as Justin called it. You need to keep in mind the extra electrons that are represented by the negative charge in BH4in.

Count the valence electrons: for three boron and one extra electron in addition to one hydrogen because it has a negative charge:

3 + 4 + 1 = 8 electrons.

So if you make a four-bond Lewis structure of four hydrogen atoms, it's going to represent eight electrons. Does not matter.

BH4 is a tetrahedral with a bond angle of 109.5 degrees.

=========== Tracking ===============

Extra electrons ??? Suppose boron trihydride (BH3) combines with sodium hydride to form NABH4 (sodium tetrahydrocarbonate).

NaH (g) + BH3 (g)> NaBH4 (s)

Sodium tetrahydrocarbon is soluble in water and when dissolved in water separates into Na + and BH4 + ions. It should now be clear where the extra electrons are coming from. In this case, it's sodium.

Lewis also has 4 structures.

Bh4 Lewis Structure

What is the structure of the [BH4] ion in relation to VSEPR, as well as the dot and cross structure? 3
I'm having trouble making dot and cross diagrams for this ion, it doesn't seem like there are any electrons left to attach to the boron for the final hydrogen. please explain.
update
I know we need extra electrons because it is a negative ion, but where do these extra electrons come from?
It's not as bad as you think, nor is it as complicated as Justin called it. You have to keep in mind the extra electrons represented by the negative charge in BH4.
Count the valence electrons: three for boron and one for hydrogen, plus one extra electron because it has a negative charge:
3 + 4 + 1 = 8 electrons.
So if you make a four-bond Lewis structure of four hydrogen atoms, it's going to represent eight electrons. Does not matter.
BH4 is a tetrahedral with a bond angle of 109.5 degrees.
=========== Tracking ==============
Extra electrons ??? Suppose boron trihydride (BH3) combines with sodium hydride to form NaBH4 (sodium tetrahydrobureate).
NaH (g) + BH3 (g)> NaBH4 (s)
Sodium tetrahydrocarbon is soluble in water and when dissolved in water dissolves in Na + and BH4 + ions. It should now be clear where the extra electrons are coming from. In this case, it is sodium.
Lewis BH4 structure
The structure of Lewis will be like a cross.
With four Hs at the four ends and B in the middle.
The weaver structure is a tetrahedron with respect to vsper.
And this molecule has a net projection.
An H is connected to the top line.
B. in the middle
The letter H is inserted in the lower left corner with a hyphen.
An H got stuck in the pitcher in the center of the bottom.
And H with the line inserted in the bottom right corner
I can think of some (theoretical) ways where extra electrons come from.
1. BH3 accepts 2 more electrons as a result of redox reaction. Reacts with strong acids so that BH3 acts as a Lewis base (in which a single electron pair is donated to H + and forms a detox bond).
I can imagine a reaction with BH3 Mg or Zn in HCl to form BH4 and MgCl2 or ZnCl2.
BH3 + Mg + 2HCl> BH4 + MgCl2 + H + ... (The result is acid XD)
2. bh3 accepts extra electrons, forms one (one, from a specific reaction), reacts with H2, breaks HH bond (lytic lysis, bond electrons go to each hydrogen). Then 2BH3 + 2H> 2BH4. s is very reactive, so this reaction is fast.
3. BH3 reacts with hydride ion (H). The extra electrons come only from H. BH3 has a duty bond with H.
By the way, a dating bond looks like a harmony bond, but the combined electrons only come from one of the paired atoms.
Ammonia, for example, is an isolated companion, right? Imae H + bonds with ammonia without electrons. The shared electrons will only come from ammonia. This is the place.
Once a bond is formed, it is no different from any other harmonious bond. Electrons are joined together like ordinary covalent bonds.
H3N: + H +> [H3N: H +]> [H3N: H] + or [NH4] +
Found? Electrons come from nh3.
For the same: BH3 for reaction 1 and H: for reaction 3
However, unless you are really curious and really want it, I don't think your teacher will ask for sure if this boron has extra electrons.
I would be happy to explain if you are interested.
: D
It's not that difficult.
There are 3 boron electrons,
4 hydrogen electrons (each)
And electrons with a negative sign.
There are eight electrons. Boron is the central atom and has eight points around the atom, then 1 hydrogen in front of each set of two points.
__H
__ ..
H: W: H
__ ..
__H
It supports curved SeO2 PF4 + tetrahedral ICl3 pe T shape.