A 1 2bh Solve For B

Solve for h: A = 1 / 2ah + 1 / 2bh Help me find the answer:? ۔

And my next question is / 3x2 /> 13, su y sign y y over 13, forget about the equals sign.

F1:

a = 1 / 2ah + 1 / 2bh.

2a = ah + bh.

h (a + b) = 2a.

h = 2a / (a + b)

Answer: h = 2a / (a + b)

P2:

| 3x 2 | > 13.

3x 2> 13.

3x> 15.

x> 5.

3x 2> 13.

3x> 11.

x> 11/3.

Answer: x> 5, x> 11/3.

T1. A = 1 / 2ah + 1 / 2bh.

A = 1/2 (a + b) gives h.

2 times we get.

2A = (a + b) h.

Divide by (a + b) {(must be different from a + b z), we get.

h = 2A / (a + b)

Second quarter | 3x2 | > = 13.

A = 1 / 2ah + 1 / 2bh.

Such as:

A = 1/2 (ah + bh)

Multiply each side by 2.

2A = ah + bh.

Such as

2A = j (a + b)

Divide each side by a + b.

(2a) / (a + b) = h.

A 1 2bh Solve For B

Solve for h: A = 1 / 2ah + 1 / 2bh Help me find the answer:? 3
And my next question is / 3x2 /> 13, su y absolute sign is greater than y y 13, forget the equals sign
F1:
a = 1 / 2ah + 1 / 2bh
2a = ah + bh
h (a + b) = 2a
h = 2a / (a + b)
Answer: h = 2a / (a + b)
P2:
| 3x 2 | > 13
3x 2> 13
3x> 15
x> 5
3x 2> 13
3x> 11
x> 11/3
Answer: x> 5, x> 11/3
T1. A = 1 / 2ah + 1 / 2bh
A = 1/2 (a + b) gives h.
Multiplying by 2 gives us.
2A = (a + b) h
Divide (a + b) {(must be different from a + b z)}, we get.
h = 2A / (a + b)
2nd quarter. | 3x2 | > = 13
A = 1 / 2ah + 1 / 2bh
Such as:
A = 1/2 (ah + bh)
Multiply each side by 2.
2A = ah + bh
Like
2A = j (a + b)
Divide each side by a + b.
(2a) / (a + b) = h